SOLUTION: There is a sequence of numbers a1, a2, ... where a1 = 2, a2 = 3, and an = (an-1)/(an-2) for n> 3. What is the value of a1485?
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-> SOLUTION: There is a sequence of numbers a1, a2, ... where a1 = 2, a2 = 3, and an = (an-1)/(an-2) for n> 3. What is the value of a1485?
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Question 974769: There is a sequence of numbers a1, a2, ... where a1 = 2, a2 = 3, and an = (an-1)/(an-2) for n> 3. What is the value of a1485? Answer by solver91311(24713) (Show Source):
If you work out the first 12 terms, you will notice a pattern:
Yes, indeed, the set of values repeats every six terms. Using integer division, divide 1485 by 6 and note the remainder. Count the number of terms in the list up to the remainder you just obtained, and that will be the value of
John
My calculator said it, I believe it, that settles it
