SOLUTION: Can you help me figure this out for myself, I see the answer I don't understand how you got it. 14. Based on the information given for the following studies, decide whether to reje

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Question 974410: Can you help me figure this out for myself, I see the answer I don't understand how you got it. 14. Based on the information given for the following studies, decide whether to reject the null hypothesis. Assume that all populations are normally distributed. For each, give:
a. The Z-score cutoff (or cutoffs) on the comparison distribution at which the null hypothesis should be rejected.
b. The Z-score on the comparison distribution for the sample score.
c. Your conclusion.
Study µ σ Sample
Score p Tails of Tests
A 5 1 7 0.05 1 (high predicted)
B 5 1 7 0.05 2
C 5 1 7 0.01 1 (High predicted)
D 5 1 7 0.01 2

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
14. Based on the information given for the following studies, decide whether to reject the null hypothesis. Assume that all populations are normally distributed.
For each, give:
a. The Z-score cutoff (or cutoffs) on the comparison distribution at which the null hypothesis should be rejected.
b. The Z-score on the comparison distribution for the sample score.
c. Your conclusion.
Study µ σSampleScore p Tails of Tests
A 5 1 7 0.05 1 (high predicted)
Cutoff:: z = 1.645
test statistic of the sample score:: (7-5)/1 = 2
Conclusion:: Since the test stat is in the reject interval, reject Ho.
-----------------------------------------------------
B 5 1 7 0.05 2
Cutoffs:: z = +/-1.96
test stat:: (7-5)/1 = 2
Conclusion:: Since the test stat is in the reject interval, reject Ho.
--------------------------------------------------------
C 5 1 7 0.01 1 (High predicted)
Cutoff:: z = 2.3264
test stat:: 2
Conclusion:: Since the test stat is not in the reject interval, do not reject Ho
-------------------------------
D 5 1 7 0.01 2
Cutoffs:: z = 2.5758
test stat:: 2
Conclusion:: Not in reject interval; do not reject Ho.
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Cheers,
Stan H.
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