Question 974400: You have a kennel that contains all Labrador Retrievers. The kennel has 3 black labs, 5 yellow labs, and 2 chocolate labs.
Finding the following probability:
* What's the probability that you draw a yellow lab on the first draw, don't put the lab back, and then draw either a yellow or chocolate lab on the second draw?
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! First Draw:
There are 5 yellow labs out of 3+5+2 = 10 labs total.
P(yellow lab) = 5/10 = 1/2
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Second Draw:
We don't put the lab back, so this is considered without replacement. There are 10-1 = 9 labs left after drawing a yellow lab. There are 5-1 = 4 yellow labs left.
There are (4 yellow)+(2 chocolate) = 6 labs that we want on the second draw out of 9 labs total leftover
P(yellow or chocolate on second draw) = 6/9 = 2/3
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Multiply the two probabilities: (1/2)*(2/3) = (1*2)/(2*3) = 2/6 = 1/3
Final Answer: 1/3
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