SOLUTION: solve the equation x^2-4x+8=0 in complex number system

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Question 974338: solve the equation x^2-4x+8=0 in complex number system
Answer by Boreal(15235) About Me  (Show Source):
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x^2-4x+8=0
quadratic formula
x= (1/2) 4+/- sqrt (16-32) ;;sqrt (-16)
=(1/2) 4+/- 4i
=2+2i; 2-2i
Check using the first
4+8i+4i^2-8-8i+8=
(4*i^2=-4)
4-4+8i-8i+8-8=0