SOLUTION: A jet leaves an airport at a speed of 350 km/h for 90 minutes in the direction of N 44* E. A second jet leaves at the same time but flies due west at a speed of 248 km/h for 90 mi
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-> SOLUTION: A jet leaves an airport at a speed of 350 km/h for 90 minutes in the direction of N 44* E. A second jet leaves at the same time but flies due west at a speed of 248 km/h for 90 mi
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Question 974230: A jet leaves an airport at a speed of 350 km/h for 90 minutes in the direction of N 44* E. A second jet leaves at the same time but flies due west at a speed of 248 km/h for 90 minutes. How far are they apart from each other after 90 minutes? Draw a diagram and solve. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! This is a Law of Cosines Problem
jet 1 has gone 525 km N44E
jet 2 has gone 372 km at a bearing of 270, which is 134 degrees apart from jet 1.
The distance apart is opposite to the angle of 134 degrees
c^2=a^2+b^2-2abcos C; c^2 is the square of the distance apart they are
c^2=525^2+372^2-2(575)(372)cos134 The last is -0.695, so the last term is positive
=843.40 km
