SOLUTION: Hi, I have this equation about the volume of a rectangle that i just can;t solve. It says, the width of a rectangular box is 4 times its height, and its length is 10 times more

Algebra ->  Volume -> SOLUTION: Hi, I have this equation about the volume of a rectangle that i just can;t solve. It says, the width of a rectangular box is 4 times its height, and its length is 10 times more      Log On


   



Question 974205: Hi,
I have this equation about the volume of a rectangle that i just can;t solve. It says, the width of a rectangular box is 4 times its height, and its length is 10 times more than its height. find the dimensions of the box if its volume is 468 cubic inches.
I rearranged this in many ways like x= (4x) (10-x) (468) but i didn't know what to do after that.
thank you

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x=height
4x=width
10x=length
You would get a 10-x if two summed to 10 and one were x. The other would be (10-x)
40x^3=468
x^3=11.7
x=11.7^(1/3)=2.27
4x=9.08
10x=22.7
22.7*9.08*2.27=467.88, close enough with rounding
2.2702*9.0808*22.7019=468.00