SOLUTION: The horizontal distance d (in feet) traveled by a projectile with an initial speed of v feet per second is modeled by: d=v squared/32 sin2 θ where θ is the angle at whic

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Question 974032: The horizontal distance d (in feet) traveled by a projectile with an initial speed of v feet per second is modeled by: d=v squared/32 sin2 θ
where θ is the angle at which the projectile is launched.
Find the horizontal distance traveled by a golf ball that is hit with an initial speed of 100 feet per second when the ball is hit at an angle of θ = 40°. Round to the nearest foot
Answer by Alan3354(69443) About Me  (Show Source):
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The horizontal distance d (in feet) traveled by a projectile with an initial speed of v feet per second is modeled by: d=v squared/32 sin2 theta
where theta is the angle at which the projectile is launched.
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Find the horizontal distance traveled by a golf ball that is hit with an initial speed of 100 feet per second when the ball is hit at an angle of θ = 40°. Round to the nearest foot
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Angle = 40 degs
v = 100 ft/sec
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Sub those numbers into the formula.