SOLUTION: An integer is divided by 7 giving a remainder of 5. The resulting quotient when divided by 5 gives a remainder of 3. The resulting quotient is then divided by 9 giving a quotient o

Algebra ->  Inverses -> SOLUTION: An integer is divided by 7 giving a remainder of 5. The resulting quotient when divided by 5 gives a remainder of 3. The resulting quotient is then divided by 9 giving a quotient o      Log On


   



Question 973988: An integer is divided by 7 giving a remainder of 5. The resulting quotient when divided by 5 gives a remainder of 3. The resulting quotient is then divided by 9 giving a quotient of 1 and a remainder of 1.
What will the finale remainder be if the order of the divisors is reversed?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(1) +a%2F7+=+b+%2B+5%2F7+
(2) +b%2F5+=+c+%2B+3%2F5+
(3) +c%2F9+=+1+%2B+1%2F9+
---------------------
(3) +c+=+9+%2B+1+
(3) +c+=+10+
and
(2) +b%2F5+=+10+%2B+3%2F5+
(2) +b+=+50+%2B+3+
(2) +b+=+53+
and
(1) +a%2F7+=+53+%2B+5%2F7+
(1) +a+=+371+%2B+5+
(1) +a+=+376+
----------------------
Reverse the order of the divisors
+a%2F9+=+376%2F9+
+376%2F9+=+41+%2B+7%2F9+
+41%2F5+=+8+%2B+1%2F5+
+8%2F7+=+1+%2B+1%2F7+
---------------------
I get a remainder of +1+ with order of
divisors reversed. You should get a 2nd
opinion on this. I may be wrong.