SOLUTION: 3 consecutive odd integers such that the product of the first and the third integers is equal to 4 less than the square of the second integer
my sides keep cancelling out, what
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-> SOLUTION: 3 consecutive odd integers such that the product of the first and the third integers is equal to 4 less than the square of the second integer
my sides keep cancelling out, what
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Question 973964: 3 consecutive odd integers such that the product of the first and the third integers is equal to 4 less than the square of the second integer
my sides keep cancelling out, what am i missing Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! 3 consecutive odd integers such that the product of the first and the third integers is equal to 4 less than the square of the second integer
my sides keep cancelling out, what am i missing
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Use n-2, n, n+2
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(n-2)*(n+2) = n^2 - 4
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It's true for any 3 odd (or even) consecutive integers.
No unique solution.
