SOLUTION: How many pounds of tea that cost $4.20 per pound must be mixed with 12 lb of tea that cost $2.25 per pound to make a mixture that costs $3.40 per pound?

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Question 97395This question is from textbook Algebra Beginning and Intermediate
: How many pounds of tea that cost $4.20 per pound must be mixed with 12 lb of tea that cost $2.25 per pound to make a mixture that costs $3.40 per pound? This question is from textbook Algebra Beginning and Intermediate

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
How many pounds of tea that cost $4.20 per pound must be mixed with 12 lb of tea that cost $2.25 per pound to make a mixture that costs $3.40 per pound?
:
Let x = amt of $4.20 tea
:
It says it will be mixed with 12 lb, therefore:
Resulting amt = (x+12)
:
4.2x + 2.25(12) = 3.4(x+12)
:
4.2x + 27 = 3.4x + 40.8
:
4.2x - 3.4x = 40.8 - 27
:
.8x = 13.8
:
x = 13.8/.8
:
x = 17.25 lb of $4.20 tea required
:
:
Check:
4.2(17.25) + 2.25(12) = 3.4(17.25+12)
72.45 + 27 = 3.4(29.25)
99.45 = 99.45, confirm our solution of x = 17.25