SOLUTION: John mixed cashews and almonds. -John bought 4 pounds of almonds for a total cost of $22. -The cost per pound for cashews is 60% more than the cost per pound for almonds.

Algebra ->  Expressions-with-variables -> SOLUTION: John mixed cashews and almonds. -John bought 4 pounds of almonds for a total cost of $22. -The cost per pound for cashews is 60% more than the cost per pound for almonds.       Log On


   



Question 973901: John mixed cashews and almonds.
-John bought 4 pounds of almonds for a total cost of $22.
-The cost per pound for cashews is 60% more than the cost per pound for almonds.
-John bought enough cashews that, when he mixed them with the almonds, the mixture had a value of $6.50 per pound.
Approximately what percent of the mixture, by weight, was cashews?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
-John bought 4 pounds of almonds for a total cost of $22.
almonds cost 22/4 = $5.50 per lb
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-The cost per pound for cashews is 60% more than the cost per pound for almonds.
1.6*5.5 = $8.80 per lb
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-John bought enough cashews that, when he mixed them with the almonds, the mixture had a value of $6.50 per pound.
Approximately what percent of the mixture, by weight, was cashews?
Equation:
value + value = value
5.5a + 8.8c = 6.50(a+c)
5.5a + 8.8c = 6.5a + 6.5c
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1a = 2.3c
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c = a/2.3
c = 0.435a
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Total weight = a + c
Total weight = 1.435a
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Percent of cashews = wt of cashews/total weight
Percent of cashews = 0.435a/1.435a = 38.3%
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Cheers,
Stan H.
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