Question 973816: It is reported that 16 percent of American households use a cell phone exclusively for their telephone service. In a sample of eight households, find the probability that:
(a) None use a cell phone as their exclusive service. (Round your answer to 4 decimal places.)
Probability:
(b) At least one uses the cell exclusively. (Round your answer to 4 decimal places.)
Probability:
(c) At least five use the cell phone. (Round your answer to 4 decimal places.)
Probability:
-Can you please help me find the probability in each scenario of A,B, and C?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! The probability that none do is (0.84^8)=0.2479
The probability that at least one will is 1- probability (0)=0.7521.
At least 5 use it
5: 8 choose 5: 56 ways *(0.16^5)(0.84^3)=0.0035
6: 8 choose 6: 28 ways *(0.16^6)(0.84^2)=0.0003
7: 8 ways (0.17^7)(0.84)=0.00003
8 will be too small.
Probability is 0.0038
The expected value is about 1, where the probability is 0.38
for 2 it is 28 *(0.84^6)(0.16^2)=0.25
For 0,1,2 using it, the probability is nearly 90%.
It is 8 choose the number using (n), multiplied by (0.84^n)(0.16^8-n)
|
|
|
