Question 973760: If a pair of dice is thrown what is the
probability of occurring neither 7 nor 11?
Found 2 solutions by Boreal, rothauserc:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! There are 36 outcomes
probability of each
2-1/36
3-2/36
4-3/36
5-4/36
6-5/36
7-6/36
8-5/36
9-4/36
10-3/36
11-2/36
12-1/36
The answer is 1-(8/36)=28/36 =(7/9)
Answer by rothauserc(4718)  (Show Source):
You can put this solution on YOUR website! 6 ways to get a 7 (4,3),(3,4)(6,1),(1,6),(5,2),(2,5)
2 ways to get 11 (5,6),(6,5)
There are 36 possible outcomes when rolling two dice, therefore
the probability of occurring neither 7 nor 11 = 1 - ( (6/36) + (2/36) ) = 0.777777778 approx 0.78
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