SOLUTION: Please help:{{{2x^2+4x-8=0}}}

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Question 973626: Please help:2x%5E2%2B4x-8=0
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!

2x^2+4x-8=0
x= (1/4) -4 +/- sqrt (16+64) ;;; sqrt (80) = 4 sqrt 5
x= -1 +/- sqrt 5
This is +1.236 and -3.236

graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C2x%5E2%2B4x-8%29