SOLUTION: Mr. Smith has $4.90 in dimes and quarters in his wallet. If he has 7 more quarters than dimes how many of each coin does he have?

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Question 973482: Mr. Smith has $4.90 in dimes and quarters in his wallet. If he has 7 more quarters than dimes how many of each coin does he have?
Found 2 solutions by CubeyThePenguin, Alan3354:
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
d = number of dimes
q = number of quarters

10d + 25q = 490
q = d + 7

Substitute the first equation into the second.

10d + 25(d + 7) = 490
10d + 25d + 175 = 490
35d = 315
d = 9

There are 9 dimes and 16 quarters.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Mr. Smith has $4.90 in dimes and quarters in his wallet. If he has 7 more quarters than dimes how many of each coin does he have?
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Set the "7 more Q's" aside.
Then it's sets of 35 cents each worth 315 cents.
315/35 = 9
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--> 9 dimes and 16 Q's