SOLUTION: I'm having difficulty trying to answer this question, help is much appreciated thank you very much. Find the sum log(a,2)+log(a,4)+log(a,8)....+log(a,1024).

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I'm having difficulty trying to answer this question, help is much appreciated thank you very much. Find the sum log(a,2)+log(a,4)+log(a,8)....+log(a,1024).      Log On


   

Question 973412: I'm having difficulty trying to answer this question, help is much appreciated thank you very much.

Find the sum log(a,2)+log(a,4)+log(a,8)....+log(a,1024).
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!

Find the sum log(a,2)+log(a,4)+log(a,8)....+log(a,1024).
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Find the sum log(a,2)+log(a,4)+log(a,8)....+log(a,1024).
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Find the sum log(a,2^1)+log(a,2^2)+log(a,2^3)....+log(a,2^10).
= log(a,2^1*2^2*2^3...2^10)
= log(a,2^(1+2+3+...10))
= log(2,2^55)
= 55*log(a,2)