SOLUTION: 1.find the equation of the line with the given slope and passing through the given point with 1 and point (-2,-2) 2.tuition fees change at university are given by f(x)=135 x +

Algebra ->  Linear-equations -> SOLUTION: 1.find the equation of the line with the given slope and passing through the given point with 1 and point (-2,-2) 2.tuition fees change at university are given by f(x)=135 x +      Log On


   



Question 973386: 1.find the equation of the line with the given slope and passing through the given point with 1 and point (-2,-2)

2.tuition fees change at university are given by f(x)=135 x + 450
3.for the line -2x + 9y =6 find
the slope
the y-intercept
the x-intercept
4.Find the x-and y- intercepts of the line 8x + 6y =24 and sketch its graph.

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
QUESTION 1:
Using slope-intercept form, m=slope
y=mx+b Put in value for slope (m=1)
y=x+b Put in values of given point to find b.
-2=-2+b Add 2 to each side.
0=b
Equation: y=(1)x+0=x so
ANSWER: y=x
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QUESTION 2:
No question asked
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QUESTION 3:
.
Put equation in slope-intercept form:
-2x+9y=6
9y=2x+6
y=(2/9)x+(2/3)
Slope is (2/9)
.
To find x-intercept set y=0
0=(2/9)x+(2/3)
-(2/3)=(2/9)x
-3=x
The x-intercept is (-3,0)
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The y-intercept is given by b (from slope-intercept form).
The y-intercept is (0,2/3)
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GRAPH:
.
+graph%28+500%2C+500%2C+-5%2C+5%2C+-5%2C+5%2C+%282%2F9%29x%2B%282%2F3%29%29+
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QUESTION 4:
8x + 6y =24
6y=-8x+24
y=-(4/3)x+4
The y-intercept is (0,4)
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For x-intercept set y=0
0=-(4/3)x+4
-4=-(4/3)x
3=x
The x intercept is (3,0)
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GRAPH:
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+graph%28+500%2C+500%2C+-5%2C+5%2C+-5%2C+5%2C+-%284%2F3%29x%2B4%29+