SOLUTION: A man is four times as old as his son. In five years time he will be three times as old. Find their present ages.

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Question 973373: A man is four times as old as his son. In five years time he will be three times as old. Find their present ages.
Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
x = age of son now
4x = age of man now

x + 5 = age of son in five years
4x + 5 = age of man in five years

4x + 5 = 3(x + 5) {in five years the man will be three times the son}
4x + 5 = 3x + 15 {used distributive property}
x + 5 = 15 {subtracted 3x from each side}
x = 10 {subtracted 5 from each side}
4x = 40 {substituted 10, in for x, into 4x}

son is 10
man is 40

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