SOLUTION: (log base 7 of x^2) +1= (log base 7 of 5). I got plus or minus (sqrt35)7. I don't know if the answer is right? thanks for your help!!

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: (log base 7 of x^2) +1= (log base 7 of 5). I got plus or minus (sqrt35)7. I don't know if the answer is right? thanks for your help!!      Log On


   

Question 973293: (log base 7 of x^2) +1= (log base 7 of 5). I got plus or minus (sqrt35)7. I don't know if the answer is right? thanks for your help!!
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
log%287%2C%28x%5E2%29%29%2B1=log%287%2C5%29

log%287%2C%28x%5E2%29%29-log%287%2C5%29=-1

log%287%2C5%29-log%287%2C%28x%5E2%29%29=1

log%287%2C%285%2F%28x%5E2%29%29%29=1

Put into exponential form:

7%5E1=5%2Fx%5E2

x%5E2%2F5=1%2F7

x%5E2=5%2F7

highlight%28x=0%2B-+sqrt%285%2F7%29%29
The included 0 was added only to help for rendering, and otherwise not necessary.
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Your mistake was in omitting the division indicator or fraction bar indicator. The rationalization should be sqrt%285%2F7%29%28%28sqrt%287%29%29%2F%28sqrt%287%29%29%29,
therefore, highlight%280%2B-+sqrt%2835%29%2F7%29.