SOLUTION: Peter is playing poker. He cashes out 3 red chips and 4 blue chips for 23 dollars, and 5 red chips and 12 blue chips for 65 dollars. How many dollars is each red chip worth?
Question 973243: Peter is playing poker. He cashes out 3 red chips and 4 blue chips for 23 dollars, and 5 red chips and 12 blue chips for 65 dollars. How many dollars is each red chip worth? Found 2 solutions by algebrahouse.com, josmiceli:Answer by algebrahouse.com(1659) (Show Source):
3r + 4b = 23 {3 red chips and 4 blue chips for $23}
5r + 12b = 65 {5 red chips and 12 blue chips for $65}
-9r - 12b = -69 {multiplied top equation by -3}
5r + 12b = 65 {bottom equation stays the same}
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-4r = -4 {added the two equations}
r = 1 {divided each side by -4}
3r + 4b = 23 {top equation}
3(1) + 4b = 23 {substituted 1 for r into top equation}
3 + 4b = 23 {multiplied}
4b = 20 {subtracted 3 from each side}
b = 5 {divided each side by 4}
You can put this solution on YOUR website! Let = the cash value of 1 red chip
Let = the cash value of 1 blue chip
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given:
(1)
(2)
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Multiply both sides of (1) by and
subtract (2) from (1)
(1)
(2)
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Each red chip is worth $1
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check:
(1)
(1)
(1)
(1)
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(2)
(2)
(2)
(2)
OK
