SOLUTION: If (a+b)^2=64 and (a−b)^2=4, what is the value of ab?

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Question 973241: If (a+b)^2=64 and (a−b)^2=4, what is the value of ab?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
a^2+2ab+b^2=64
a^2-2ab+b^2=4
Multiply the second equation by (-1)
-a^2+2ab-b^2= -4;; now add the two.
4ab=60
ab=15
5 and 3 are the coefficients.