Question 973236: I need help solving this rational expression. Here is the problem:
2x-3/x+4 = x-3/x-4
How do I solve for this RE? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! 2x-3/x+4 = x-3/x-4
Multiply the whole equation by (x-4) (x+4). OR Cross-multiply.
(2x-3) (x-4) = (x-3) (x+4) One of the two terms you are multiplying by cancels the denominator.
Now distribute.
2x^2-11x+12= x^2+x-12
x^2 -12x +24=0
(1/2) [12 +/- sqrt (144-96)]
(1/2) [12 +/- 4 sqrt (3)]
6+ 2sqrt (3) = 9.464
6-2 sqrt (3)
Substitute the numerical value in
(15.928/13.464) = 6.464/5.464
1.1830 ; 1.1830