SOLUTION: Express the following in regtangular form by using De Moivre's formulae? Z = [3(cos 3pi/2 + jsin 3pi/2)]^3

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Question 973181: Express the following in regtangular form by using De Moivre's formulae?
Z = [3(cos 3pi/2 + jsin 3pi/2)]^3
Answer by Alan3354(69443) About Me  (Show Source):
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Express the following in regtangular form by using De Moivre's formulae?
Z = [3(cos 3pi/2 + jsin 3pi/2)]^3
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Z = [3cis(3pi/2)]^3
Z = 3^3cis(9pi/2) = 27cis(pi/2)
Z = 27cos(pi/2) + jsin(pi/2)
Z = 0 + 27j
Z = 27j