SOLUTION: What are the real solutions to the equation: abs (x) squared + 2 abs(x) - 3 = 0? Answer choices: A. +/- 1 B. +/- 3 C. 1 and 3 D. -1 and -3 E. +/-1 and +/-3 Thank yo

Algebra ->  Absolute-value -> SOLUTION: What are the real solutions to the equation: abs (x) squared + 2 abs(x) - 3 = 0? Answer choices: A. +/- 1 B. +/- 3 C. 1 and 3 D. -1 and -3 E. +/-1 and +/-3 Thank yo      Log On


   



Question 973146: What are the real solutions to the equation:
abs (x) squared + 2 abs(x) - 3 = 0?
Answer choices:
A. +/- 1
B. +/- 3
C. 1 and 3
D. -1 and -3
E. +/-1 and +/-3

Thank you for your help and explanation.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Remove the absolute value bars, and then solve the resulting quadratic equation. If you find that you have real roots, test each into the equation with the absolute value bars. Any real number that makes a true statement when substituted for the independent variable in the original equation is an element of the solution set. If a number substituted creates a false statement, then that number is not an element of the solution set.

John

My calculator said it, I believe it, that settles it