SOLUTION: you have a jar of coins containing nickels and quarters worth $1.55. The money jar contains 11 coins. Find out how many coins of each type you have using a system of equations.
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Question 973114: you have a jar of coins containing nickels and quarters worth $1.55. The money jar contains 11 coins. Find out how many coins of each type you have using a system of equations. Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
N=nickels; Q=quarters
N+Q=11
N=11-Q Use this to substitute for N.
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$0.05N+$0.25Q=$1.55 Substitute for N.
$0.05(11-Q)+$0.25Q=$1.55
$0.55-$0.05+$0.25Q=$1.55
$0.20Q=$1.00
Q=5 ANSWER 1: There are 5 quarters.
N=11-Q=11-5=6 ANSWER 2: There are 6 nickels.
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CHECK:
$0.05N+$0.25Q=$1.55
$0.05(6)+$0.25(5)=$1.55
$0.30+$1.25=$1.55
$1.55=$1.55
