SOLUTION: The area of a rectangular restaurant kitchen is 80 square meters. The perimeter is 36 meters. What are the dimensions of the kitchen?

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Question 973110: The area of a rectangular restaurant kitchen is 80 square meters. The perimeter is 36 meters. What are the dimensions of the kitchen?
Found 2 solutions by Boreal, macston:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Area = length*width
2L +2W=36 meters; L+W=18 meters, dividing both sides by 2.
L*W=80 sq meters But L=18-W
(18-W)*W=80
-W^2+18W=80
W^2-18W=-80, multiplying by (-1)
W^2-18W+80=0
(W-10)(W-8)=0
Width can be 10 or 8; by convention, we take the width as the lesser.
Width is 8
Length is 10
Perimeter is 2(18)=36 m.
Area is 8*10 m^2.

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
L=length; W=width
P=2(L+W)
36m=2(L+W)
18m=L+W
18m-W=L Use this to substitute for L.
.
A=LW Substitute for L.
80m%5E2=%2818m-W%29%28W%29
80m%5E2=18W-W%5E2
0=-W%5E2%2B18W-80
0=W%5E2-18W%2B80
0=%28W-8%29%28W-1%29
W-8=0 or W-10=0
W=8 or W=10
When width=8m, length=18m-w=18m-8m=10m.
When width=10m length=18m-10m=8m
Dimensions are either 8m x 10m or 10m x 8m.