SOLUTION: Jen Butler has been pricing speed pass train fares for a group trip to new york. Three adults and four children must pay $100.00. Two adults and three children must pay $70.00.Find

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Jen Butler has been pricing speed pass train fares for a group trip to new york. Three adults and four children must pay $100.00. Two adults and three children must pay $70.00.Find      Log On


   

Question 973074: Jen Butler has been pricing speed pass train fares for a group trip to new york. Three adults and four children must pay $100.00. Two adults and three children must pay $70.00.Find the price of the adults ticket and the price of the childs ticket.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
A=Adult price; C=Child price
3A+4C=$100 Multiply by 2.
6A+8C=$200 Use this to subtract below.
.
2A+3C=$70 Multiply by 3.
. 6A+9C=$210 Subtract equation from above.
-(6A+8C=$200)
C=$10 ANSWER 1: One child's fare is $10
.
3A+4C=$100
3A+4($10)=$100
3A+$40=$100
3A=$60
A=$20 ANSWER 2: One adult's fare is $20
.
CHECK:
2A+3C=$70
2($20)+3($10)=$70
$40+$30=$70
$70=$70