SOLUTION: The number of green beads varied inversely as the square of the number of yellow beads. When there were 8 green, there were 5 yellows. How many would there be if threre were 10 yel

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: The number of green beads varied inversely as the square of the number of yellow beads. When there were 8 green, there were 5 yellows. How many would there be if threre were 10 yel      Log On


   



Question 97297: The number of green beads varied inversely as the square of the number of yellow beads. When there were 8 green, there were 5 yellows. How many would there be if threre were 10 yellows?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The number of green beads varied inversely as the square of the number of yellow beads.
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green = k/(yellow)^2
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When there were 8 green, there were 5 yellows.
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8 = k/(5)^2
k = 200
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Equation for this relation is g = 200/y^2
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How many would there be if there were 10 yellows?
g = 200/(10)^2
g = 200/100
g = 2 green beans when there are 10 yellow
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Cheers,
Stan H.