Question 972925: 2 years ago I was 4 times my sons age. 8 years ago I was 10 times his age.
How old is he now? Found 2 solutions by Boreal, macston:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! my age=x; son's age=y
11 years old ANSWER.
x-2=4*(y-2)
x-8=10*(y-8)
x=4y-8+2=4y-6
x=10y-80+8=10y-72
10y-72=4y-6
6y=66
y=11 son's age
two years earlier, son was 9, you were 36
you are 38 now.
eight years ago, you were 30, son was 3.
You can put this solution on YOUR website! .
Y=your age; S=son's age
.
Y-2=4(S-2)
Y-2=4S-8
Y=4S-6 Use this to substitute for Y below.
.
Y-8=10(S-8)
Y-8=10S-80
Y=10S-72 Substitute for Y from above.
4S-6=10S-72 Subtract 4S from each side.
-6=6S-72 Add 72 to each side.
66=6S
11=S ANSWER: The son is currently 11 years old.
.
CHECK:
Y-2=4(S-2)
Y-2=4(11-2)
Y-2=4(9)
Y-2=36
Y=38 You are currently 38 years old
.
Y-8=10(S-8)
38-8=10(11-8)
30=10(3)
30=30
