Praying that someone out there can help me assist my daughter with this problem.
Two girls went on a run. Cary began running 40 seconds earlier than Kristie.
*Cary ran at a speed of 10 feet per second
*Kristie ran at a speed of 12 feet per second
For how many seconds had Cary been running at the moment when the two girls had ran exactly the same distance.
This problem falls under "Linear equations and proportions."
Any feedback would be greatly appreciated.
Thanks in advance.
Let time it would take Cary to get to “meeting point” be T
Then time it would take Kristie to get to “meeting point” is: T – 40
Distance covered by Cary when they meet: 10T
Distance covered by Kristie when they meet: 12(T – 40), or 12T – 480
When they meet, they would cover the same distance
Therefore, we get: 10T = 12T – 480
10T – 12T = - 480
– 2T = - 480
T, or time Cary would take to get to “meeting point” =
, or