SOLUTION: A sphere of radius Z is inscribed inside a cube of side length 4. Let v be a vertex of the cube. Let s be the set of points inside the cube and outside the sphere which are close

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Question 972793: A sphere of radius Z is inscribed inside a cube of side length 4. Let v be a vertex of the cube. Let s be the set of points inside the cube and outside the sphere which are closer to v than any other vertex on the cube. What is the volume of s?
Answer by Alan3354(69443) About Me  (Show Source):
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A sphere of radius Z is inscribed inside a cube of side length 4. Let v be a vertex of the cube. Let s be the set of points inside the cube and outside the sphere which are closer to v than any other vertex on the cube. What is the volume of s?
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The total volume outside the sphere and in the cube is
4%5E3+-+4pi%2Az%5E3%2F3
The cube has 8 vertices --> the volume asked for = 4%5E3+-+4pi%2Az%5E3%2F3 over 8.
= 8+-+pi%2Az%5E3%2F6
That volume includes points closer to a vertex AND equidistant from an adjacent vertex.
--> Vol < 8+-+pi%2Az%5E3%2F6