SOLUTION: there are two different copper alloys of total weight 50 kilograms. the first contains 40%less copper than the second one. determine the percentage of copper in first alloy . if it
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Question 972640: there are two different copper alloys of total weight 50 kilograms. the first contains 40%less copper than the second one. determine the percentage of copper in first alloy . if it is known that there were 6 kg copper in first alloy and 12 kilograms in second alloy. what is the percentage of copper in second alloy? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! there are two different copper alloys of total weight 50 kilograms
let x = amt of the 1st alloy
then
(50-x) amt of the 2nd alloy
:
the first contains 40%less copper than the second one. determine the
Use the decimal equiv of percent
"percentage of copper in first alloy if it is known that there were 6 kg copper in first alloy and 12 kilograms in second alloy. what is the percentage of copper in second alloy?" = percent copper in the 1st alloy (in decimal form)
and = percent copper in the 2nd alloy
:
"the first contains 40%less copper than the second one.",
40% less means the 1st alloy copper is .6 of the 2nd alloy, therefore:
.6* =
. =
Cross multiply
7.2x = 6(50-x)
7.2x = 300 - 6x
7.2x + 6x = 300
13.2x = 22.73 kg, the amt of the 1st alloy
then
50-22.73 = 27.27 kg, the amt of the 2nd alloy
"what is the percentage of copper in second alloy?" * 100 = 44% copper in the 2nd alloy
:
:
Check this by finding the percent copper in the 1st alloy * 100 = 26.4%
Find the relationship to the copper in te 2nd alloy * 100 = 60% which is 40% less than the 2nd alloy copper
