SOLUTION: wallace and vernonville are 176 miles apart. A car leaves wallace traveling towards vernonville and another car leave vernonville at the same time, traveling towards wallace. The c

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Question 972623: wallace and vernonville are 176 miles apart. A car leaves wallace traveling towards vernonville and another car leave vernonville at the same time, traveling towards wallace. The car leaving wallace averages 10 miles per hour more than the other, and they meet after 1 hour and 36 minutes. What are the average speeds of the cars?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
For this problem, you can think of one car
standing still and the other one traveling
at the sum of their speeds
---------------------------
Let +s+ = the speed of the slower car
+s+%2B+10+ = the speed of the faster car
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Convert +36+ min to hrs:
+36%2F60+=+.6+ hrs
--------------------------
I can say:
+176+=+%28+s+%2B+s+%2B+10+%29%2A1.6+
+176+=+%28+2s+%2B+10+%29%2A1.6+
+176+=+3.2s+%2B+16+
+3.2s+=+160+
+s+=+50+
and
+s+%2B+10+=+60+
The average speeds are 50 mi/hr and 60 mi/hr
-----------------------
check:
With both of the cars moving instead:
Slower car:
+d%5B1%5D+=+50%2A1.6+
+d%5B1%5D+=+80+
Faster car:
+d%5B2%5D+=+60%2A1.6+
+d%5B2%5D+=+96+
-------------------
+d%5B1%5D+%2B+d%5B2%5D+=+80+%2B+96+
+d%5B1%5D+%2B+d%5B2%5D+=+176+ mi
OK