Question 972556: The sum of the two smaller of the three consecutive numbers exceeds the largest by 52. Find the numbers Found 2 solutions by Boreal, lwsshak3:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! smallest=x
x+x+1-52=x+2
2x-51=x+2
x=53
the numbers are 53, 54, and 55
53+54 are 52 more than 55.
You can put this solution on YOUR website! The sum of the two smaller of the three consecutive numbers exceeds the largest by 52. Find the numbers.
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let x=smallest of three consecutive numbers
x+1=next smallest of three consecutive numbers
x+2=largest of three consecutive numbers
..
x+(x+1)=x+2 (sum of the two smaller of the three consecutive numbers exceeds the largest by 52)
2x+1=x+2+52
x=53
smallest of three consecutive numbers=53
next smallest of three consecutive numbers=54
largest of three consecutive numbers=55
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