SOLUTION: find a real number that exceeds its cube by 2.

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Question 97253This question is from textbook
: find a real number that exceeds its cube by 2. This question is from textbook

Found 2 solutions by Nate, edjones:
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
x = x^3 + 2
Obviously, the number is negative.
Between -2 and -1 ...
graph%28300%2C300%2C-5%2C5%2C-5%2C5%2Cx%5E3+-+x+%2B+2%29
About -1.52

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
x=x^3+2
x^3-x+2=0 (no factors)
x=-1.5213797 (TI calculator)
x^3=-3.5213797
Ed