SOLUTION: domain and range of function f(x)=(x^2-2x+5)^1/2

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Question 972440: domain and range of function
f(x)=(x^2-2x+5)^1/2
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
roots of the function:
[2 +/- sqrt (4-20)]/2 This is[ 2 +/- 4i]/2= 1+/- 2i
There are no real roots, so the function never becomes negative.
That means x can be any number, so domain is all reals
Range is >0
vertex has an x-value of 1 and a y-value of 2 ; (vert x value is -b/2a. That is 2/2; x=1, y=2).
Therefore, the range is y greater than or equal to 2.
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