SOLUTION: Find the area between y = −x^2−11 x−18 and the x-axis.

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Question 972422: Find the area between y = −x^2−11 x−18 and the x-axis.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x-ints at -9 and -2
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INT = -x^3/3 - 11x^2/2 - 18x (ignore the C)
INT(-9) = 243 - 891/2 + 162 = -81/2
INT(-2) = 8/3 - 22 + 36 = 50/3
Diff = 343/6 sq units
Area = 343/6 sq units