SOLUTION: my question is about how to solve log equations with a function thing as an exponent. An example would be log base 5 of 5 ^x-5.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: my question is about how to solve log equations with a function thing as an exponent. An example would be log base 5 of 5 ^x-5.      Log On


   

Question 972372: my question is about how to solve log equations with a function thing as an exponent. An example would be log base 5 of 5 ^x-5.
Found 2 solutions by MathLover1, Boreal:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
log%285%2C%285%5E%28x-5%29%29%29
=%28x-5%29log%285%2C%285%29%29....since log%285%2C%285%29%29=1, we have
=x-5

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
log5 (5^x-5)= x-5
log to the base of something of the same something =1. log to the base of something of the same something raised to the power is the power. Here it is in numerical form:
log10 10=1
ln e=1
log 10 (10^2)=2 ;; log (100)=2
log5 5^3=log5 125=3
You can also put the exponent out in front.
log5 5^(x-5)=
(x-5) log5 (5)=x-5