You can
put this solution on YOUR website! Solve. |x²+6| = 5x
Since x²+6 is always positive we do not need the absolute values,
however we must restrict the right side 5x to always be positive
too. 5x > 0, therefore x > 0
|x²+6| = 5x x > 0
x²+6 = 5x
x²-5x+6 = 0
(x-2)(x-3) = 0
x-2=0; x-3=0
x=2; x=3
They both came out positive so we do not need to say x > 0 or to
discard a solution. Both are solutions:
Edwin