SOLUTION: This problem was similar to the other one I asked about. Perpendicular to the line y=2x-3;containing the point (1,-2) My answer was y=-1/2x and 1 1/2. My teacher remarked "use impr
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-> SOLUTION: This problem was similar to the other one I asked about. Perpendicular to the line y=2x-3;containing the point (1,-2) My answer was y=-1/2x and 1 1/2. My teacher remarked "use impr
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Question 97226: This problem was similar to the other one I asked about. Perpendicular to the line y=2x-3;containing the point (1,-2) My answer was y=-1/2x and 1 1/2. My teacher remarked "use improper fractions" He wanted this graphed and two x y charts, mine were definitely wrong. Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! y=mx+b m=slope
y=2x-3 m=2 b=-3
a line perpendicular to any line has slope of -1/m. Since m=2 then -1/m=-1/2=-.5
y-y[1]=m(x-x[1]) point slope form.
For the perpendicular line: y-(-2)=-.5(x-1)) "containing the point (1,-2)"
y+2=-.5(x-1)
y+2=-.5x+.5
subtract 2 from both sides. y=-.5x-1.5
Ed
Ed
