SOLUTION: a bag contains 8 red and 5 white balls.two successive draws of 3 balls are made without replacement.the probability that the first draw will produce 3 white balls and the second 3
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Question 972129: a bag contains 8 red and 5 white balls.two successive draws of 3 balls are made without replacement.the probability that the first draw will produce 3 white balls and the second 3 red balls is?
I want solution for above question.
answer is 7/429
i m not getting how it comes....kindly send solution...verry urgent.. Found 2 solutions by Boreal, Alan3354:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! 13 balls.
First three balls are white, with no replacement (5/13)(4/12)(3/11)= 60/1716
Now the second draw are red (8/10)((7/9)(6/8)= 336/720.
Multiply these, for this is a joint probability
(60/1716) * (336/720)
Cancel 60 and 720
(1/1716) * (336/12)
Work on second term
(1/1716)*28
Divide by 4 numerator and denominator
(7/429)
You can put this solution on YOUR website! a bag contains 8 red and 5 white balls.two successive draws of 3 balls are made without replacement.the probability that the first draw will produce 3 white balls and the second 3 red balls is?
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For the 3 white balls:
= 5/13, 4/12, 3/11 = 5/143
For the 3 red balls:
8/10, 7/9, 6/8 = 7/15
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7/15 * 5/143 = 7/429
