SOLUTION: I need help with this problem:
The number of bacteria in a certain culture increased from 600 to 1800 between 7:00am and 9:00am. Assuming growth is exponential, the number of f(
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-> SOLUTION: I need help with this problem:
The number of bacteria in a certain culture increased from 600 to 1800 between 7:00am and 9:00am. Assuming growth is exponential, the number of f(
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Question 972050: I need help with this problem:
The number of bacteria in a certain culture increased from 600 to 1800 between 7:00am and 9:00am. Assuming growth is exponential, the number of f(t) bacter1a t hours after 7:00am is given by f(t)=600(3)^(t/2).
a. Estimate the number of bacteria in the culture at 8:00am, 10:00am, and 11:00am.
b. Sketch the graph of f for 0<=t<=4.
Any help would be greatly appreciated. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! at 1 hour f(1)=600* 3^(1/2)=1039
at 3 hours f(3)=600* 3 ^(3/2)=3118
at 4 hours f(4)=600*3 ^(4/2)=5400
Ignore the negatives on the graph. It formats better if I put them in.
