SOLUTION: A has P5.35 in 5 cents,10 cents and 25 cents. The number of 10 cents coins is one more than twice the number of 5 cents coins. How many of each kind of coins does A have?

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Question 971974: A has P5.35 in 5 cents,10 cents and 25 cents. The number of 10 cents coins is one more than twice the number of 5 cents coins. How many of each kind of coins does A have?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
n, d, q, the count of five cent, ten cent, and twenty-five cent coins.

system%280.05n%2B0.1d%2B0.25q=5.35%2Cd=1%2B2%2An%29

system%28n%2B2d%2B5q=107%2Cd=2n%2B1%29

n%2B4n%2B2%2B5q=107

5n%2B5q=105

n%2Bq=21

You could try a revised system of
system%28n%2Bq=21%2Cd=2n%2B1%29 and look for any combinations that will work. You need natural numbers only. Try starting with q=1, solve for n, and see what this gives you for the d equation; and then work upwards for q. Maybe you could have more than one solution.