SOLUTION: Thank you so much! I already found parts a, b and c (not listed to save space), but I need help with part d... Given {{{ f(x) = (5x-5)/(x^2-3x+2) }}} and {{{ g(x) = 5/(x-2) }}}

Algebra ->  Rational-functions -> SOLUTION: Thank you so much! I already found parts a, b and c (not listed to save space), but I need help with part d... Given {{{ f(x) = (5x-5)/(x^2-3x+2) }}} and {{{ g(x) = 5/(x-2) }}}       Log On


   

Question 971892: Thank you so much! I already found parts a, b and c (not listed to save space), but I need help with part d...
Given +f%28x%29+=+%285x-5%29%2F%28x%5E2-3x%2B2%29+ and +g%28x%29+=+5%2F%28x-2%29+ , explain how the two functions differ.
I already found the domain of f(x) to be all real numbers except 2 and 1, and the domain of g(x) to be all real numbers except 2, if that helps at all. I also found the vertical asymptote of f(x) to be +5%2F-2+
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
%285x-5%29%2F%28x%5E2-3x%2B2%29

%285%28x-1%29%29%2F%28%28x-2%29%28x-1%29%29

highlight%28%285%2F%28x-2%29%29%28%28x-1%29%2F%28x-1%29%29%29

x=1 IS NOT a vertical asymptote; instead, the factor of 1 forces f(x) to EXCLUDE any value for x=1, because f(x) is not defined for x=1.