SOLUTION: You invest $5000 in two stocks. In one year, the value of stock A increases by 9.8% and the value of stock B increases by 6.2%. The total value of the stocks is now $ 5389.20 How m

Algebra ->  Finance -> SOLUTION: You invest $5000 in two stocks. In one year, the value of stock A increases by 9.8% and the value of stock B increases by 6.2%. The total value of the stocks is now $ 5389.20 How m      Log On


   

Question 971886: You invest $5000 in two stocks. In one year, the value of stock A increases by 9.8% and the value of stock B increases by 6.2%. The total value of the stocks is now $ 5389.20 How much did you originally invest in each stock?
Found 2 solutions by Boreal, josmiceli:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x=invested in stock a
5000-x = invested in stock b
x *.098= gain on stock a
(5000-x) * (.062)= gain on stock b
.098x +310-.062x = 389.20 (5389.20-5000)
.036 x +310 -389.20
.036 x =79.20
x=$2200 stock a
5000-x=$2800 stock b
2200*.098= $215.60
2800*.062= $173.60
they add to $389.20

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = amount invested in stock A
+5000+-+x+ = amount invested in stock B
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+x+%2B+.098x+%2B+5000+-+x+%2B+.062%2A%28+5000+-+x+%29+=+5389.2+%29+
+1.098x+%2B+1.062%2A%28+5000+-+x+%29+=+5389.2+
+1.098x+%2B+5310+-+1.062x+=+5389.2+
+.036x+=+5389.2+-+5310+
+.036x+=+79.2+
+x+=+2200+
and
+5000+-+x+=+2800+
$2,200 was invested in stock A
$2,800 was invested in stock B
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check:
+1.098x+%2B+1.062%2A%28+5000+-+x+%29+=+5389.2+
+1.098%2A2200+%2B+1.062%2A2800+=+5389.2+
+2415.6+%2B+2973.6+=+5389.2+
+5389.2+=+5389.2+
OK