SOLUTION: a jar contains n nikles and d dimes. there is a total of 200 coins in the jar.the value of the cions is $14.00.how manu nickles and how many dimes are in the jar?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: a jar contains n nikles and d dimes. there is a total of 200 coins in the jar.the value of the cions is $14.00.how manu nickles and how many dimes are in the jar?       Log On

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Question 971695: a jar contains n nikles and d dimes. there is a total of 200 coins in the jar.the value of the cions is $14.00.how manu nickles and how many dimes are in the jar?

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
will do with 2 variables.
n+d=200
.05 n + .10 d= 14.00
n=200-d
.05 (200-d) +.10d=14.00
10.00-.05d +.10d=14.00
.05d =4.00, by collecting terms
5d=400 after multiplying by 100.
d=80
n=120
120*.05 =$6 for nickels
80 dimes=$8
Total $14