SOLUTION: Tina and Mary leave their college at the same time. Tina walks to the West while Mary rides her bike to the East, going 1 mph slower than five times Tina's speed walking. Two hours
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Question 971573: Tina and Mary leave their college at the same time. Tina walks to the West while Mary rides her bike to the East, going 1 mph slower than five times Tina's speed walking. Two hours later they are 34 miles apart. How fast was Tina walking? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Tina and Mary leave their college at the same time. Tina walks to the West while Mary rides her bike to the East, going 1 mph slower than five times Tina's speed walking. Two hours later they are 34 miles apart. How fast was Tina walking?
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let x=Tina's speed walking
5x-1=Mary's's speed riding her bike
speed at which Mary and Tina traveling apart=x+(5x-1)=6x-1
distance /speed=travel time
34/(6x-1)=2
12x-2=34
12x=36
x=3
How fast was Tina walking? 3 mph
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