SOLUTION: Can anyone help me figure this out?
Period of a Pendulum The period T(in seconds) of a simple pendulum as a function of its length l (in feet) is given by 32.2 ( ) 2 l T l = 	
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-> SOLUTION: Can anyone help me figure this out?
Period of a Pendulum The period T(in seconds) of a simple pendulum as a function of its length l (in feet) is given by 32.2 ( ) 2 l T l = 	
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Question 971451: Can anyone help me figure this out?
Period of a Pendulum The period T(in seconds) of a simple pendulum as a function of its length l (in feet) is given by 32.2 ( ) 2 l T l = π
(a) Express the length l as a function of the period T.
(b) How long is a pendulum whose period is 3 seconds?
Thank you in advance! Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! T(l) = 2pi * square root(l/g) where g is 32.2 feet per second per second
now solve for l
a) T/(2pi) = square root(l/g)
square both sides of =
(T/(2pi))^2 = l/32.2
l = 32.2 * (T/(2pi))^2
b) if T (period) is 3 seconds then
l = 32.2 * (3/(2pi))^2
l = 32.2 * 0.227972663
l = 7.340719753
length of pendulum is 7.340719753 feet
