SOLUTION: homeowner wishes to insulate her attice with fiberglass insulation to conserve energy. The insulation comes in 40 cm wide rolls that are cut to fit between the rafters in the attic
Algebra ->
Radicals
-> SOLUTION: homeowner wishes to insulate her attice with fiberglass insulation to conserve energy. The insulation comes in 40 cm wide rolls that are cut to fit between the rafters in the attic
Log On
Question 97131: homeowner wishes to insulate her attice with fiberglass insulation to conserve energy. The insulation comes in 40 cm wide rolls that are cut to fit between the rafters in the attic, if the roof is 7 m from peak to eave and the attic space is 3m high at the peak, how long does each of the pieces of insulation need to be? Round to the nearest tenth. Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! HERE YOU HAVE A RIGHT TRIANGLE WITH THE SIDE OF 3 METERS & THE HYPOTENUSE OF 7 METERS.
USING THE PYTHAGOREAN THEORUM A^2+B^2=C^2 YOU HAVE:
3^2+B^2=7^2
9+B^2=49
B^2=49-9
B62=40
B=SQRT40
B=6.3 METERS LONG.
PROOF
9+6.3^2=49
9+40=49
49=49