SOLUTION: A collection of coins consisting of quarters and dimes amounts to $7.65. twice the number of quarters is equal to 11 less than 3 times the number of dimes. how many of each coin i

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: A collection of coins consisting of quarters and dimes amounts to $7.65. twice the number of quarters is equal to 11 less than 3 times the number of dimes. how many of each coin i      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 971304: A collection of coins consisting of quarters and dimes amounts to $7.65.
twice the number of quarters is equal to 11 less than 3 times the number of dimes. how many of each coin is there?

Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
d = number of dimes
q = number of quarters

10d + 25q = 765
2q = 3d - 11 ----> 3d - 2q = 11

Multiply the first equation by 2 and the second equation by 25.

20d + 50q = 1530
75d - 50q = 275
-------------------------
95d = 1805
d = 19

There are 19 dimes and 23 quarters.